Counting Even & Odd Elements In Array (C#.net)

The following code shows you how to count even and odd elements in an array. And displaying the counted numbers on console.

Code

public static void Main(string[] args)

{

     

     int[] arr = { 2, 3, 1, 5, 6, 4, 7, 8, 9, 11, 10 };

     int size = arr.Length;

    

     evenOddElements(arr,size);

}

public void evenOddElements(int[] arr, int size)

{

     int even = 0, odd = 0;

     for (int i = 0; i < size; i++)

     {

         if (arr[i] % 2 == 0)

         {

            even++;

         }

         else

         {

            odd++;

         }

     }

    Console.WriteLine("Even Array Elements Are : " + even);

    Console.WriteLine();

    Console.WriteLine("ODD Array Elements Are : " + odd);

}

Output of the program is:

Even Array Elements Are : 5

Odd Array Elements Are : 6